81 lines
3.2 KiB
Python
81 lines
3.2 KiB
Python
# This program is written by: https://github.com/polarwinkel/mdtex2html
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from latex2mathml.converter import convert as tex2mathml
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import re
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incomplete = '<font style="color:orange;" class="tooltip">⚠<span class="tooltiptext">formula incomplete</span></font>'
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convError = '<font style="color:red" class="tooltip">⚠<span class="tooltiptext">LaTeX-convert-error</span></font>'
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def convert(mdtex, extensions=[], splitParagraphs=True):
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''' converts recursively the Markdown-LaTeX-mixture to HTML with MathML '''
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found = False
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# handle all paragraphs separately (prevents aftereffects)
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if splitParagraphs:
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parts = re.split("\n\n", mdtex)
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result = ''
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for part in parts:
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result += convert(part, extensions, splitParagraphs=False)
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return result
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# find first $$-formula:
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parts = re.split('\${2}', mdtex, 2)
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if len(parts)>1:
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found = True
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result = convert(parts[0], extensions, splitParagraphs=False)+'\n'
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try:
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result += '<div class="blockformula">'+tex2mathml(parts[1])+'</div>\n'
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except:
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result += '<div class="blockformula">'+convError+'</div>'
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if len(parts)==3:
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result += convert(parts[2], extensions, splitParagraphs=False)
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else:
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result += '<div class="blockformula">'+incomplete+'</div>'
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# else find first $-formulas:
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else:
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parts = re.split('\${1}', mdtex, 2)
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if len(parts)>1 and not found:
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found = True
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try:
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mathml = tex2mathml(parts[1])
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except:
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mathml = convError
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if parts[0].endswith('\n\n') or parts[0]=='': # make sure textblock starts before formula!
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parts[0]=parts[0]+'​'
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if len(parts)==3:
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result = convert(parts[0]+mathml+parts[2], extensions, splitParagraphs=False)
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else:
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result = convert(parts[0]+mathml+incomplete, extensions, splitParagraphs=False)
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# else find first \[..\]-equation:
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else:
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parts = re.split(r'\\\[', mdtex, 1)
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if len(parts)>1 and not found:
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found = True
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result = convert(parts[0], extensions, splitParagraphs=False)+'\n'
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parts = re.split(r'\\\]', parts[1], 1)
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try:
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result += '<div class="blockformula">'+tex2mathml(parts[0])+'</div>\n'
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except:
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result += '<div class="blockformula">'+convError+'</div>'
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if len(parts)==2:
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result += convert(parts[1], extensions, splitParagraphs=False)
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else:
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result += '<div class="blockformula">'+incomplete+'</div>'
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# else find first \(..\)-equation:
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else:
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parts = re.split(r'\\\(', mdtex, 1)
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if len(parts)>1 and not found:
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found = True
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subp = re.split(r'\\\)', parts[1], 1)
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try:
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mathml = tex2mathml(subp[0])
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except:
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mathml = convError
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if parts[0].endswith('\n\n') or parts[0]=='': # make sure textblock starts before formula!
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parts[0]=parts[0]+'​'
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if len(subp)==2:
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result = convert(parts[0]+mathml+subp[1], extensions, splitParagraphs=False)
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else:
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result = convert(parts[0]+mathml+incomplete, extensions, splitParagraphs=False)
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if not found:
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result = mdtex
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return result
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